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A man walks in a certain direction for 5 km and then walks in the south direction for 4 km. If he ends up in the east direction with respect to the starting position, how far is he from the starting position ?
2 km
3 km
4 km
5 km
- The man first walks 5 km in a certain direction.
- Next, he walks south for 4 km.
- He ends up in an eastward position relative to the starting point.
To find the distance from the starting position:
- He forms a right-angled triangle with:
- Adjacent side (horizontal component): 5 km (east)
- Opposite side (vertical component): 4 km (south)
- Use the Pythagorean theorem a2+b2=c2:
- c=52+42
- c=25+16
- c=41
- c≈6.4 km
Options summary:
- None of the listed options match ≈6.4 km.
- Hence, no correct option.
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