Explanation:

Let’s break down the problem with the Rs 1, Rs 2, and Rs 5 coins.

We need combinations such that:

1x + 2y + 5z = 10, where x, y, z are non-negative integers.

Possible combinations (for every z = 0 to 2, the max Rs 5 coins you can use):

- z = 0: (all Rs 1 and Rs 2)

- x + 2y = 10

- y = 0, x = 10

- y = 1, x = 8

- y = 2, x = 6

- y = 3, x = 4

- y = 4, x = 2

- y = 5, x = 0

? 6 ways.

- z = 1: (one Rs 5 coin)

- x + 2y = 5

- y = 0, x = 5

- y = 1, x = 3

- y = 2, x = 1

? 3 ways.

- z = 2: (two Rs 5 coins)

- x + 2y = 0

- y = 0, x = 0

? 1 way.

- Add them: 6 + 3 + 1 = 10 ways.

- So, option 3 (10 ways) is correct.

- The other options (8, 9, 11) don’t match the combinations above.

Correct Answer: Option 3 (10 ways)