Multiple Choice Questions

Tap A can fill an empty tank alone in 6 hours Tap B alone can empty the same tank when filled in 8 h...........

Quantitative Aptitude (MTS) Pipes&cistern

Tap A can fill an empty tank alone in 6 hours. Tap B alone can empty the same tank, when filled, in 8 hours. If they are

opened in alternate hours starting with A, then in how much time will the tank be full for the first time?

This questions was previously asked in

SSC MTS 5th July 2022 Shift-2

44 hours

48 hours

41 hours

47 hours

- Tap A can fill the tank alone in 6 hours. This means it fills 1/6 of the tank per hour.

- Tap B can empty the tank in 8 hours. This means it empties 1/8 of the tank per hour.

- They work in alternate hours: starting with Tap A filling the tank for 1 hour, followed by Tap B emptying the tank for 1 hour.

- In 2 hours, the net effect would be: (1/6 - 1/8) of the tank filled.

- Simplifying (1/6 - 1/8), you get a net fill of 1/24 per 2-hour period.

- To fill the whole tank, you need 24 such 2-hour cycles.

- Thus, time required = 24 periods * 2 hours/period = 48 hours.

- Correct Answer: Option 2: 48 hours

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