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What is the compound interest on Rs24,000 for 2 years at the rate of 10% per annum, if interest is compounded annually?
Rs5,280
Rs4,820
Rs6,080
Rs5,040
To calculate compound interest, we use the formula:
$$ A = P \left(1 + \frac{r}{n}\right)^{nt} $$
Where:
- \( A \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount (Rs24,000 in this case).
- \( r \) is the annual interest rate (10%, or 0.10).
- \( n \) is the number of times interest is compounded per year (annually, so 1).
- \( t \) is the number of years the money is invested or borrowed (2 years).
- Plug in the values:
$$ A = 24000 \times \left(1 + \frac{0.10}{1}\right)^{1 \times 2} $$
- After calculations:
$$ A = 24000 \times (1.10)^2 = 24000 \times 1.21 = 29040 $$
- Therefore, Compound Interest = \( A - P = 29040 - 24000 = 5040 \)
- Option 1: Rs5,280
- Option 2: Rs4,820
- Option 3: Rs6,080
- Option 4: Rs5,040
The compound interest is Rs5,040.
By: santosh ProfileResourcesReport error
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