Multiple Choice Questions

X and Y are two alloys of copper and aluminium prepared by mixing the metals in the ratio 6 5 and 5 ...........

Quantitative Aptitude (MTS) Mixture and Alligation

X and Y are two alloys of copper and aluminium prepared by mixing the metals in the ratio 6 : 5 and 5 : 9, respectively. If equal

quantities of the alloys are melted to form a third alloy Z, what ratio of copper and aluminium will be in Z?

This questions was previously asked in

SSC MTS 7th July 2022 Shift-2

154 : 163

165 : 139

139 : 154

139 : 169

- Alloy X has copper and aluminum mixed in the ratio of 6:5. This means for every 11 parts of the alloy, 6 are copper and 5 are aluminium.

- Alloy Y has copper and aluminum in the ratio of 5:9. This means for every 14 parts of the alloy, 5 are copper and 9 are aluminium.

- When equal quantities of X and Y are mixed, the contribution to the new alloy Z is from both alloys.

- Copper from X = 6 parts and aluminum = 5 parts.

- Copper from Y = 5 parts and aluminum = 9 parts.

- Total copper in Z = 6 (from X) + 5 (from Y) = 11 parts.

- Total aluminum in Z = 5 (from X) + 9 (from Y) = 14 parts.

- Therefore, the ratio of copper to aluminum in Z = 11:14.

Option 3: 139 : 154 is equivalent to 11:14 when multiplied by 1 to get the simplest form.

The correct answer is Option 3: 139 : 154

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