Multiple Choice Questions

120 apples 240 oranges and 150 pears are packed in ca11ons in such a way that each ca11on has the sa...........

Quantitative Aptitude (MTS) Profit and loss

120 apples, 240 oranges and 150 pears are packed in ca11ons in such a way that each ca11on has the same number of fmits,

each car1on contains only one type of fmit, and no fmit is left unpacked. What is the smallest possible number of canons

needed for the purpose?

This questions was previously asked in

SSC MTS 8th July 2022 Shift-3

- We need to find the largest number that divides perfectly into the quantities of each fruit to ensure all fruits are packed without leftovers.

- The quantities of fruits are 120 apples, 240 oranges, and 150 pears.

- We need the greatest common divisor (GCD) of these numbers.

- Calculate GCD:

- Factors of 120: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120.

- Factors of 240: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240.

- Factors of 150: 1, 2, 3, 5, 6, 10, 15, 25, 30, 50, 75, 150.

- The greatest common factor is 30.

- Divide each fruit quantity by GCD (30):

- Apples: 120 ÷ 30 = 4 cartons.

- Oranges: 240 ÷ 30 = 8 cartons.

- Pears: 150 ÷ 30 = 5 cartons.

- Total cartons: 4 (apples) + 8 (oranges) + 5 (pears) = 17 cartons.

- Option 3: 17 is correct.

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