The speed of Ashu is 15 km h more than the speed of Vishu They start moving in the same direction at...........

Quantitative Aptitude (MTS) Time & distance

The speed of Ashu is 15 km/h more than the speed of Vishu. They start moving in the same direction at the same time, but

initially Vishu is ahead of Ashu by a certain distance. If Ashu crosses Vishu 6 hours after they start moving, what is

the initial distance between them?

This questions was previously asked in

SSC MTS 11th July 2022 Shift-1

80 km

45 km

60 km

90 km

- Ashu's speed is 15 km/h more than Vishu's speed.

- They start at the same time, heading in the same direction, with Vishu initially ahead by a certain distance.

- Ashu overtakes Vishu after 6 hours of starting.

- The distance Ashu covers more than Vishu in 6 hours is the initial distance between them.

Let's assume Vishu’s speed is \( x \) km/h. Then Ashu’s speed is \( x + 15 \) km/h.

- Distance covered by Ashu in 6 hours = \( 6 \times (x + 15) \)

- Distance covered by Vishu in 6 hours = \( 6 \times x \)

The initial distance between them:

- Ashu covers \( 6 \times 15 \) km more than Vishu in these 6 hours.

- So, initial distance = \( 90 \) km.

- Option:1, 80 km - Incorrect

- Option:2, 45 km - Incorrect

- Option:3, 60 km - Incorrect

- Option:4, 90 km - Correct

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