Explanation:

- We have 32 consecutive numbers. Split them into two groups: the first 13 and the next 19.

- The average of the first 13 numbers is denoted by x.

- Let's say the first number in the sequence is n.

- The first 13 numbers will be from n to (n + 12). Therefore, the sum is 13n + 78. The average is x = (13n + 78) / 13.

- The next 19 numbers range from (n + 13) to (n + 31). The sum is 19n + 418.

- The average of these 19 numbers is (19n + 418) / 19.

- Solve both parts to find that the second average is x + 19.

?? Upon reviewing: None of the listed options appear correct based on the given problem. .