Multiple Choice Questions on Find the second smallest number which when divided by 81 or 63 leaves a remainder of 7 in each case ........ for SSC (MTS) Preparation

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Multiple Choice Questions

Find the second smallest number which when divided by 81 or 63 leaves a remainder of 7 in each case ........

Quantitative Aptitude (MTS) Number System
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    Find the second smallest number which, when divided by 81 or 63 , leaves a remainder of 7 in each case.

    This questions was previously asked in
    SSC MTS 15th July 2022 Shift-2
    View All SSCMTS Previous Year Papers

    1246

    Incorrect Answer

    1141

    Correct Answer

    1362

    Incorrect Answer

    1137

    Incorrect Answer
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    Explanation:

    Correct option is 2: 1141
    LCM of (81,63) = 567
    The smallest number = 567k + 7 when k = 1
    The second smallest number = 567k + 7 when k = 2
    Hence, the required number = 567x 2+7
    1134+7=1141
    .. The required smallest number is 1141.

    By: santosh
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