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There are eight persons, A, B, C, D, E, F, G and H, all having different weights. Only two persons are lighter than F. F is heavier
than A but lighter than B. D is lighter than E but heavier than G. H is lighter than A. C is heavier than E. C is not the heaviest
person. The weights of the second heaviest and the second lightest persons are 78 kg and 48 kg, respectively.
How many persons are lighter than the person who is just lighter than D?
One
Three
Four
Two
- Start by deciphering the weight order with given clues. Only two are lighter than F, implying F is third lightest.
- A is lighter than F, so A is either first or second. H is lighter than A, making H the lightest. Order so far: H, A, F.
- E is heavier than D, and D is heavier than G. Align them: G, D, E.
- C is not the heaviest but heavier than E, thus C is second heaviest.
- With C second heaviest, remaining heaviest is B. Order: H, A, F, G, D, E, C, B.
- Qualified positions: G is fourth, with three (H, A, F) lighter than him.
Correct Answer: Option: 2, Three
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