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There are two numbers such that the first number is three times of the second number. If the average of these two numbers is 72, then what is the first number?
108
54
36
64
Correct option 1: 108
Calculation: Let the 1st no. be 'x' and 2nd no. be 'y' then => x=3y According to the question, 72 = (x+y) / 2
or
72 = (3y+y) / 2
Solving we get =>y = 36 Since, x = 3y then ⇒x=3 x 36 = 108 The first number is 108.
By: santosh ProfileResourcesReport error
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