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In a group 6 girls and 4 boys, four children are to be selected. In how many different ways can they be selected such that at least one girl should be there?
214
206
210
209
Sure, let’s break this down step by step:
- We have 6 girls and 4 boys—so 10 kids total.
- Selecting 4 kids with at least one girl. That means out of the 4 selections, we can’t have zero girls.
- First, let’s figure out total ways to select 4 from 10:
\(\binom{10}{4} = 210\)
- Out of these, how many groups have no girls? That’s just 4 boys, so:
\(\binom{4}{4} = 1\)
- So, groups with at least one girl = total - all boys
\(210 - 1 = 209\)
Let’s connect this to your options:
- Option 1: 214 (Too high)
- Option 2: 206 (Too low)
- Option 3: 210 (That’s total, not at least one girl)
- Option 4: 209 (This is right)
209 is the correct answer. Here's why: it’s all combinations minus the only case where there’s not a single girl in the team. That’s the only way to make sure you never get a group without a girl.
By: Parvesh Mehta ProfileResourcesReport error
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