send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
The length, the breadth, and the height of a closed cardboard box are in the ratio of 5 : 3 : 7, respectively. Find the length of this
box, if its total surface area is 1278 .cm2
20 cm
15 cm
25 cm
10 cm
To find the length of the cardboard box:
- It's given that length : breadth : height = 5 : 3 : 7.
- Let the common ratio be x.
- Therefore, length = 5x, breadth = 3x, and height = 7x.
- The total surface area of a closed box = 2(lb + bh + hl).
- Given surface area = 1278 cm².
- Substitute values: 2(5x·3x + 3x·7x + 7x·5x) = 1278.
- This simplifies to 2(15x² + 21x² + 35x²) = 1278.
- Solving: 2(71x²) = 1278 -> 142x² = 1278.
- Divide both sides by 142: x² = 9.
- x = 3 (since length cannot be negative).
- Therefore, length = 5x = 5·3 = 15 cm.
- Option 2: 15 cm is the correct answer.
Report error
Access to prime resources