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What is the greatest number of 4-digits which is divisible by 45, 25 and 5?
9000
9990
8900
9900
To find the greatest 4-digit number divisible by 45, 25, and 5, we need the least common multiple (LCM) of these numbers.
- 45 = 3 x 3 x 5
- 25 = 5 x 5
- 5 = 5
- LCM takes the highest power of each prime: 3² x 5² = 225
- Find the largest 4-digit number divisible by 225 by dividing 9999 by 225, which gives approximately 44.44.
- Multiply 225 by 44 to get 9900.
Therefore, the greatest 4-digit number divisible by 45, 25, and 5 is 9900 .
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