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To do a certain work, the ratio of the efficiencies of A, B and C is 7 : 5 : 6. Working together, they can complete the same work
in 35 days. B and C work together for 21 days. The remaining work will be completed by A alone in:
54 days
50 days
60 days
57 days
- A, B, and C have efficiency in the ratio 7:5:6.
- Together, they complete the work in 35 days.
- Total work is 35 times the combined efficiency of A, B, and C.
- The combined efficiency of A, B, and C is 7+5+6 = 18 units per day.
- Total work = 18 x 35 = 630 units.
- B and C together work at the efficiency of 5+6 = 11 units per day.
- B and C work for 21 days, completing 21 x 11 = 231 units.
- Remaining work = 630 - 231 = 399 units.
- A’s efficiency is 7 units per day.
- Time taken by A to complete 399 units = 399 ÷ 7 = 57 days.
- Therefore, the correct option is option:4 - 57 days.
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By: santosh ProfileResourcesReport error
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