Two cyclists X and Y start at the same time from place A and go towards place B at a speed of 6 km h...........

Quantitative Aptitude (CGL) Time & distance

Two cyclists X and Y start at the same time from place A and go towards place B at a speed of 6 km/h and 8 km/h,respectively.

Despite stopping for 15 minutes during the journey, Y reaches 10 minutes earlier than X. The distance between the places A

and B is:

This questions was previously asked in

SSC CGL 6th March 2020 Shift-2

6 km

16.5 km

8 km

10km

- Cyclist X travels at 6 km/h.

- Cyclist Y travels at 8 km/h.

- Y has a 15-minute stop but still reaches 10 minutes earlier than X.

- Let's calculate the time taken for both cyclists to cover distance D:

- Time for X = D/6

- Time for Y = D/8 + 15/60 (for stop)

- Given that Y reaches 10 minutes earlier:

- D/6 = D/8 + 1/4 + 1/6 (in hours: 10 minutes is 1/6 and 15 minutes is 1/4)

- Solving the equation gives D = 6 * 10/3 = 10 km

- Therefore, Option 4: 10 km is correct.

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