send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
The population of a city increased by 30%in the first year and decreased by 15% in the next year. If the present population is
11.050 then the population 2 years ago was:
10,000
99,500
99,000
10,050
- Let's assume the population two years ago was P.
- First year: Population increased by 30%:
- New population = P+0.3P=1.3P.
- Second year: Population decreased by 15%:
- New population = 1.3P×0.85=1.105P.
- Current population is given as 11,050.
- We set up the equation: 1.105P=11050.
- Solve for P by dividing both sides by 1.105:
- P=110501.105≈10,000.
- Option 1: 10,000 - This is the correct answer.
- Option 2: 99,500 - Incorrect if solving the equation.
- Option 3: 99,000 - Doesn't match the calculation result.
- Option 4: 10,050 - Close but not precise.
Report error
Access to prime resources