A train running at 48 km h crosses a man going with the speed of 12 km h in the same direction in 18...........

Quantitative Aptitude (CGL) Time & distance

A train running at 48 km/h crosses a man going with the speed of 12 km/h, in the same direction, in 18 seconds and passes a

woman coming from the opposite direction in 12 seconds. The speed (in km/h) of the woman is :

This questions was previously asked in

SSC CGL 23rd August 2021 Shift-3

- The train moves at 48 km/h.

- The man is moving in the same direction at 12 km/h.

- Relative speed between train and man = 48 - 12 = 36 km/h.

- Train crosses the man in 18 seconds.

- Distance covered in 18 seconds = 36 * (18/3600) km = 0.18 km.

- Train crosses the woman in 12 seconds.

- Relative speed between train and woman = 0.18 * (3600/12) = 54 km/h.

- Relative speed (train and woman) = train speed + woman's speed.

- 54 = 48 + woman's speed.

- Woman's speed = 54 - 48 = 6 km/h.

- Correct Answer: Option 1 - 6 km/h

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