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Two circles of radius 15 cm and 37 cm intersect each other at the points A and B. If the length of common chord is 24 cm, what
is the distance (in cm) between the centres of the circles?
44
45
42
40
Let’s break it down:
- Let the radii be r1 = 15 cm and r2 = 37 cm.
- Let the distance between the centres = d cm.
- The common chord’s length is 24 cm, so from the centre to the chord (perpendicularly) is v(r1² - 12²) and v(r2² - 12²) for respective circles.
- d = v(r1² - 12²) + v(r2² - 12²)
- Let’s calculate:
- v(15² - 12²) = v(225 - 144) = v81 = 9
- v(37² - 12²) = v(1369 - 144) = v1225 = 35
- d = 9 + 35 = 44 cm
Option:1, 44 is correct.
- Option:2 (45), Option:3 (42), Option:4 (40) are incorrect, as the calculations do not match.
By: santosh ProfileResourcesReport error
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