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A trader bought twoarticles for Rs490. Hesold one at a loss of 20% and the other at a profit of 16%.If the selling price of both
articles is same, then the cost price (in Rs) of the article sold at 20% loss is:
310
300
290
280
Let the cost price of the first article (sold at 20% loss) be Rs x.
So, the cost price of the second article (sold at 16% profit) is Rs (490 – x).
- Selling price of the first article = 80% of x = 0.8x
- Selling price of the second article = 116% of (490 – x) = 1.16×(490 – x)
- Since both selling prices are the same:
0.8x = 1.16(490 – x)
- Solve for x:
0.8x = 568.4 – 1.16x
0.8x + 1.16x = 568.4
1.96x = 568.4
x = 568.4 / 1.96 = 290
The correct answer is Option 3: 290
By: santosh ProfileResourcesReport error
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