Explanation:

- A rhombus has all sides equal in length. In this case, each side is 13 cm.

- The diagonals of a rhombus bisect each other at right angles.

- Given one diagonal is 24 cm, let's call it diagonal \(AC\).

- Let the other diagonal be \(BD\). They intersect at point \(O\).

- Since diagonals bisect each other, \(AO = 12\) cm and \(BO = x\) cm.

- Use Pythagoras' theorem in \(\triangle AOB\):

- \(13^2 = 12^2 + x^2\)

- Solving, \(169 = 144 + x^2\)

- \(x^2 = 25\)

- \(x = 5\)

- Full \(BD\) diagonal is \(2 \times 5 = 10\) cm.

- Area of rhombus = \(\frac{1}{2} \times 24 \times 10 = 120\) cm².

- Option 1 is correct: 120 cm².

Option: 1 - 120