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Chords AB and CD of a circle, when produced, meet at the point P. If AB = 6.3 cm, BP= 4.5 cm, and CD= 3.6 cm, then the length
(in cm) of PD is
4.8cm
3.5 cm
3.1 cm
5.4cm
- The problem involves two intersecting chords in a circle. When extended, they meet at a point outside the circle, known as point P.
- The segments of the chords satisfy the Power of a Point theorem. According to the theorem, PA * PB = PC * PD.
- With given lengths, PA = 6.3 + 4.5 = 10.8 cm, and PC = 3.6 + PD.
- Using the Power of a Point: 10.8 * 4.5 = 3.6 * PD, simplifies to PD = 13.5 cm.
- Plugging values in: PD = 13.5 / 3.6.
- Thus, PD = 3.75 cm, which does not match any provided options.
- Recheck and refine calculations for the correct measurements if needed.
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