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Three years ago, the ratio of the age of father to that of his son was 8 : 3. After 4 years, their ages will be in the ratio 11 : 5. What
is the present age (in years) of the father.
52
51
48
55
- Let's denote the father's age three years ago as 8x and the son's age three years ago as 3x.
- After three years, the father's age will be 8x+3+4=8x+7 and the son's age will be 3x+3+4=3x+7.
- We are told that after these four more years, the age ratio becomes 11:5.
- Setting up the equation, 8x+73x+7=115.
- Solving gives 5(8x+7)=11(3x+7).
- This simplifies to 40x+35=33x+77.
- Simplifying further, 7x=42 gives x=6.
- Thus, the present age of the father is 8x+3, which equals 51.
- Option 1: 52 - Incorrect, slightly above the calculated age.
- Option 2: 51 - Correct. This matches our calculation.
- Option 3: 48 - Incorrect, below the calculated age.
- Option 4: 55 - Incorrect, above the calculated age.
- The correct answer is Option 2: 51.
.
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