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A hollow closed cube of side 10 cm, each weighing 200 gm, is made. This cube is placed in water with a horizontal face. How many cm of its height sinks in water if the density of water is 1 gm per cm3 ?
1 cm
1.5 cm
2 cm
2.5 cm
- The cube is hollow, closed, and has a side of 10 cm.
- Volume of cube = 10 cm × 10 cm × 10 cm = 1000 cm³.
- Weight of cube = 200 gm.
- Density of water = 1 gm/cm³.
- Cube floats, so weight of water displaced = weight of cube.
- Let x be the height submerged.
- Volume submerged = 10 × 10 × x = 100x cm³.
- Weight of water displaced = 100x gm.
- Set 100x = 200 gm ? x = 2 cm.
- Option 3: 2 cm is the correct answer.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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