Explanation:

- You are given two equations based on the conditions stated.

- When x is reduced by 2 and y is increased by 2, the ratio is 2:1:

- $(x-2)/(y+2)=2/1$

- When x is increased by 2 and y is reduced by 2, the ratio becomes 3:1:

- $(x+2)/(y-2)=3/1$

- Solve the equations:

1. From $(x-2)/(y+2)=2/1$, we get:

- $x-2=2(y+2)$

- $x=2y+6$

2. From $(x+2)/(y-2)=3/1$, we get:

- $x+2=3(y-2)$

- $x=3y-6$

- By solving $2y+6=3y-6$, we get $y=12$.

- Substitute $y=12$ into $x=2y+6$:

- $x=2(12)+6=30$.

- So, $x-y=30-12=18$.

- The correct option for $x-y$ is:

Option 3, 18 ??