Explanation:

- Given two parallel chords PQ and RS in a circle.

- Length of PQ is 10 cm and length of RS is 24 cm.

- Both chords are on the same side of the center O.

- The distance between the two chords is 7 cm.

- We need to find the radius of the circle.

For calculating the radius of the circle:

- Use the formula for the distance from the center to a chord `d`: \(d = \sqrt{r^2 - \left(\frac{c}{2}\right)^2}\), where `c` is the chord length and `r` is the radius.

- Apply it separately for both chords.

For PQ (10 cm):

- Distance from center \(d_1 = \sqrt{r^2 - 5^2}\).

For RS (24 cm):

- Distance from center \(d_2 = \sqrt{r^2 - 12^2}\).

- Given \(d_2 - d_1 = 7\).

- By solving you get radius `r` as 13 cm.

Option 2: 13