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A woman sold her earphone for Rs2,000 and got a percentage profit equal to the numerical value of cost price. The cost price of
the earphone is:
Rs 500
Rs 200
Rs 600
Rs 400
- Let's say the cost price of the earphone is Rs \( x \).
- The percentage profit is also equal to \( x \).
- Selling Price (SP) = Cost Price (CP) + Profit
- Rs 2000 = \( x + \left(\dfrac{x \times x}{100}\right) \)
- \( 2000 = x + \dfrac{x^2}{100} \)
- \( 2000 \times 100 = 100x + x^2 \)
- \( x^2 + 100x - 200000 = 0 \)
- We solve this quadratic equation for \( x \).
- Solving \( x^2 + 100x - 200000 = 0 \) gives us possible cost prices.
- Checking options:
- Option 4 (Rs 400): If the cost price is Rs 400, then the profit is 400% which means the selling price = \( 400 + \frac{(400 \times 400)}{100} \).
- This calculation shows RS 2000 as the selling price.
So, the correct option is Option 4 (Rs 400).
By: santosh ProfileResourcesReport error
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