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The population of village has been continuously increasing at the rate of 10% per year. If its present population is 54,450, what
was it two years ago?
48000
45000
52000
50000
- The population is increasing at a rate of 10% per year.
- Present population is 54,450.
- We want to find what the population was two years ago.
To find this, we'll reverse calculate using the formula for compound interest:
P=A(1+r)n
Where:
- A is the amount in present terms (54,450).
- r is the rate of increase (10% or 0.10).
- n is the number of years (2).
Calculate:
P=54450(1+0.10)2=544501.21=45,000
- Option 1: 48,000 - Too high, as back-calculated population was lower.
- Option 2: 45,000 - This is correct.
- Option 3: 52,000 - Close but still above the accurate calculation.
- Option 4: 50,000 - A higher number than the calculated back population.
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