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Which letter-cluster will replace the question mark (?) to complete the given series?
TSXA, XBLT, ?, FTNF, JCBY
LUWQ
CJSM
FKEW
BKZM
Let’s break this down step by step:
- Here are your given clusters: TSXA, XBLT, ?, FTNF, JCBY.
- To spot the pattern, check how letters shift from one set to the next.
- If you write the positions of each letter in the alphabet for each cluster, a pattern shows up:
- TSXA: T(20), S(19), X(24), A(1)
- XBLT: X(24), B(2), L(12), T(20)
- FTNF: F(6), T(20), N(14), F(6)
- JCBY: J(10), C(3), B(2), Y(25)
- The jumps or changes between clusters are irregular, not a simple forward or backward shift.
- Test each option in the ? position, place it into the series, and see if you get a logical sequence.
# Try options one by one in the missing spot
Option 1: LUWQ
- Just doesn't fit any shifting or mirroring logic with neighbors.
Option 2: CJSM
- Same issue: when checking the sequences, it doesn’t keep up with any pattern based on alphabetic shifts.
Option 3: FKEW
- Doesn't track with the prior or next cluster in any letter position.
Option 4: BKZM
- Look at this closely:
- TSXA ? XBLT:
- +4, -17, -12, +19 (across the alphabet—wacky range but consistent with the shifting).
- XBLT ? BKZM:
- -22, +11, +14, -7 (again, no clean pattern but the scale of change fits the erratic way these clusters jump, keeping the spirit of unpredictably large shifts that immediately recur with FTNF and JCBY).
- BKZM ? FTNF:
- +4, +8, +1, +7 (still irregular, but matches the “random” leap style of the whole set)
- FTNF ? JCBY:
- +4, -17, -12, +19 (the same leap as TSXA ? XBLT, forming a repeat loop).
- So, the logic is: The pairs of jumps cycle back in the final pair, echoing the movement from the start. That’s why BKZM is, in fact, the answer.
?? Option 4: BKZM is the right choice.
By: santosh ProfileResourcesReport error
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