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What value must be given to ‘*’ to make 6347*25 exactly divisible by 11?
1
2
8
0
Let's break it down:
- The rule for 11: If you take the difference between the sum of the digits in odd positions and the sum in even positions, the result should be 0 or a multiple of 11.
- The number is 6 3 4 7 * 2 5 (from left).
- Odd positions: 5 (rightmost), 2, 7, 3 (counting from the right, so 5, 2, *, 7, 4, 3, 6).
- Even positions: *, 4, 6 (again, from the right).
- Odd-position sum: 5 + * + 7 + 3 = (* + 15)
- Even-position sum: 2 + 4 + 6 = 12 (the actual grouping is 5th right, 3rd, 1st for odd, but either way, we'll stick with the above logic for simplicity).
- So, Alternating sum: (6+4+*+5) - (3+7+2)
= (6+4+*+5) = (15+*)
= (3+7+2) = 12
= So, (15 + *) - 12 = * + 3
- For divisibility by 11, this must be a multiple of 11.
- Possible values for *: 8, since 8+3=11.
- Let’s check options:
- 1 ? 1+3=4 (not multiple of 11)
- 2 ? 2+3=5 (not multiple of 11)
- 8 ? 8+3=11
- 0 ? 0+3=3 (not multiple of 11)
So, here’s the thing:
Option 3: 8 is the only correct answer.
By: santosh ProfileResourcesReport error
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