In a 1200 m race the ratio of the speeds of two contestants Meenal and Nitu is 5 7 If Meenal has a s...........

Quantitative Aptitude (CHSL) Time & distance

In a 1200 m race, the ratio of the speeds of two contestants Meenal and Nitu is 5:7. If Meenal has a start of 500 m,then Meenal

wins by:

This questions was previously asked in

SSC CHSL 9th June 2022 Shift-1

220 m

240 m

250 m

225 m

- Both contestants are running a 1200 m race.

- Meenal has a starting advantage (lead) of 500 meters.

- The speed ratio of Meenal to Nitu is given as 5:7.

- This means for every 5 meters Meenal runs, Nitu runs 7 meters.

Let's calculate:

- Meenal effectively needs to cover 700 meters (1200 m race - 500 m start).

- When Meenal runs 5 meters, Nitu runs 7 meters.

- For Meenal to complete 700 meters, Nitu covers (700 / 5) * 7 = 980 meters.

- Therefore, Nitu runs 980 meters when Meenal finishes her 700 meters.

- Meenal wins by 220 meters (1200 m - 980 m).

- Correct Answer: Option 1, 220 m

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