Explanation:

- Given: 13th January 2006 is a Friday.

- We need to find the day of the week for 28th March 2008.

- First, let's count the total number of days between the two dates:

- From 13 Jan 2006 to 13 Jan 2008 is 2 years. 

- 2006 is not a leap year, but 2008 is a leap year (since 2008/4=502).

- Days from 13 Jan 2006 to 13 Jan 2007 = 365 days (regular year).

- Days from 13 Jan 2007 to 13 Jan 2008 = 365 days.

- From 13 Jan 2008 to 28 Mar 2008:

* Jan: 18 days (from 13th to 31st)

* Feb: 29 days (leap year)

* Mar: 28 days

* Total = 18 + 29 + 28 = 75 days

- Total Days = 365 + 365 + 75 = 805 days.

- 805 mod 7 = 0, so the day remains the same as Friday after every 7 days. But let's double-check the math:

- 805/7 = 115 weeks, 0 days remainder.

- So, 28th March 2008 will fall on a Friday.

Options:

- Option 1: Sunday

- Option 2: Friday

- Option 3: Saturday

- Option 4: Monday

Option 2 - Friday is correct.