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In a panchayat election Candidate A secured 30% of the total votes and did NOT qualify by 6 votes. Candidate B secured 40% of
the total votes and got 6 votes more than the bare minimum to qualify. The total number of votes were _________.
100
160
140
120
- Candidate A secured 30% of the total votes and did not qualify by 6 votes. This implies that A received votes amounting to 30% of the total minus 6 votes.
- Candidate B secured 40% of the total votes and qualified with 6 votes more than required. This means B received votes amounting to 40% of the total plus an extra 6 votes.
- For both scenarios to meet these criteria, the difference between A's votes and B's must be exactly 12 votes (6 more than the bare minimum for B and 6 less than the bare minimum for A).
- If we assume the total votes are 120:
- Candidate A receives 30% of 120 ˜ 36 votes.
- Candidate B receives 40% of 120 ˜ 48 votes.
- Difference = 48 - 36 = 12 votes, which matches the criteria perfectly.
Correct Answer: Option 4 - 120
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