PQ and RS are two parallel chords of a circle such that PQ is 48 cm and RS is 40 cm If the chords ar...........

Quantitative Aptitude (CPO) Geometry

PQ and RS are two parallel chords of a circle such that PQ is 48 cm and RS is 40 cm. If the chords are on the opposite sides of

the centre and the distance between them is 22 cm, what is the radius (in cm) of the circle?

This questions was previously asked in

SSC CPO 9th Nov 2022 Shift 2

- We have two chords, PQ and RS, each on opposite sides of the circle's center.

- PQ measures 48 cm, whereas RS measures 40 cm.

- The distance between these chords is given as 22 cm.

- The challenge is to find the radius of the circle.

- By utilizing the properties of circles and applying the Pythagorean theorem, we can find the radius.

- Construct perpendiculars from the center to PQ and RS. Let these distances be a and b from the center, respectively.

- Use the equations: \((\frac{PQ}{2})^2 + a^2 = r^2\) and \((\frac{RS}{2})^2 + b^2 = r^2\).

- Solve these equations with the condition \(a + b = 22 cm\).

?? Correct Answer: Option 1: 25 cm

- With the given parameters, solving yields the radius as 25 cm.

- Option 1 is accurate for this problem.

Submit Error