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Deepa starts from her house and cycles 4 km towards the north and then turns left and cycles 6 km. She again turns left and
cycles for X km to reach her school. Point A is to the east of her school and also 3 km to the south of her house. What is the
value of X?
1 km
7 km
9 km
3 km
Here’s the thing—let’s lay out exactly what’s happening:
- Deepa heads 4 km north from her house.
- Then she turns left (which means now she’s facing west), goes 6 km.
- She turns left again (now heading south), cycles X km, and reaches her school.
- There’s one more clue: Point A is east of the school and 3 km south of her house.
Let’s get visual:
- After moving 4 km north and 6 km west, to get in line with her starting point, she’d need to travel 4 km south. But her real destination (the school) must align with point A, which is 3 km south of her house.
- That means Deepa should travel only 1 km south (since she's already gone up 4 km, and the school is 3 km below the house).
Now, about the options:
- 1 km: That fits—the required southward distance.
- 7 km: That’s if she wanted to go "back" to the starting horizontal line, but not needed here.
- 9 km and 3 km: They don’t fit the clues or the geometry.
So the right answer is
1 km (Option 1)
The reason is simple: School just needs to be 1 km south after the final left turn. All the steps line up around this.
By: santosh ProfileResourcesReport error
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