Geeta runs 5 2 times as fast as Babita In a race if Geeta gives a lead of 40 m to Babita find the di...........

Quantitative Aptitude (CPO) Time & distance

Geeta runs 5/2 times as fast as Babita. In a race, if Geeta gives a lead of 40 m to Babita, find the distance from the starting point

where both of them will meet (correct up to two decimal places).

This questions was previously asked in

SSC CPO 10th Nov 2022 Shift 1

66.67 m

65 m

65.33 m

66 m

- Geeta runs 5/2 times faster than Babita. This means if Babita's speed is \( x \), then Geeta's speed is \( \frac{5}{2}x \).

- Babita gets a lead of 40 meters. Therefore, when the race begins, Babita has a head start of 40 meters.

- At some point, the distance covered by both from the starting point will be equal.

- The time taken for Geeta to cover the same distance as Babita (plus 40m) is calculated by equating their distance equations.

- Let the distance from the starting point be \( D \).

- Both travel the distance \( D \) simultaneously. Solving \((D - 40)/x = D/(\frac{5}{2}x)\) gives \( D = 66.67 \) m.

- Among the options, 66.67 m is the correct answer.

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