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Let x = 224 and,y = 322. If the highest common factor of 23x and a×y is divisible by x and y, then what can be the possible value
of a?
16
8
12
4
- Let's analyze the problem:
- x=224 and y=322.
- We have to find HCF(23x,a×y).
- This HCF must be divisible by both x and y.
- Calculate 23x=23×224.
- We want HCF(23×224,a×322) to be divisible by both 224 and 322.
- If a=8:
- a×y=8×322.
- Check if the HCF of 23×224 and 8×322 can be divisible by both 224 and 322.
- Correct Answer: Option 2: 8
-
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