Explanation:

- Let's break it down. Six students: A, B, C, D, E, F, all sitting around a table, all facing the center.

- The clues:

- A is next to D and E.

- C is next to D and F.

- F is next to C and B.

- Let's piece this together:

- If A is between D and E, placement looks like D–A–E.

- C is next to D (so put C next to D, options are C–D–A or D–A–E–C).

- F is next to C and B, so the only way F can be next to C (who is already near D or E) is for F to sandwich between C and B.

- Fill in the gaps: D–A–E–(someone)–B–C–F.

- Rapid check—C is paired up with D and F; that works if you put C between D and F, like D–C–F.

- But A has to be next to D and E, so A fits between D and E: D–A–E.

- Place C next to D: D–A–E, with C on the other side of D: C–D–A–E.

- Put F next to C: F–C–D–A–E.

- Now, F must be next to B as well, so B must be next to F: ...E–B–F–C–D–A...

- Let’s go around the table: A sits between D and E. C sits between D and F. F is between C and B.

- So: D–A–E–B–F–C–(loops back to D).

- The immediate neighbours of A are D and E. The immediate neighbours of B are E and F. Both A and B are next to E.

- So, option 3, E is the answer.

Simple logic, no frills.