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Two circles touch each other externally. The radius of the first circle with centre A is 18cm. The radius of the second circle with
centre B is 8cm.Find the length of their
common tangent CD.
23 cm
26 cm
24 cm
25 cm
Here are the details and explanation for the problem:
- Two circles touch each other externally, meaning the distance between their centers equals the sum of their radii.
- The radius of the first circle (center A) is 18 cm.
- The radius of the second circle (center B) is 8 cm.
- The distance between the centers A and B = 18 cm + 8 cm = 26 cm.
- A property of tangents to circles touching each other externally is that the length of the common tangent is given by \(\sqrt{AB^2 - (r_1 - r_2)^2}\).
- Here, \(AB = 26\) cm and \(r_1 - r_2 = 18 - 8 = 10\) cm.
- Calculate the length of the tangent: \(\sqrt{26^2 - 10^2} = \sqrt{676 - 100} = \sqrt{576} = 24\) cm.
The correct option is:
- Option 3: 24 cm
Correct Answer: 24 cm
By: santosh ProfileResourcesReport error
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