Multiple Choice Questions

A thief was spotted by a policeman from a distance of 225 metres When the policeman started the chas...........

Quantitative Aptitude (CHSL) Time & distance

A thief was spotted by a policeman from a distance of 225 metres. When the policeman started the chase, the thief also started

running. If the speed of the thief was 11 km/h and that of the policeman was 13 km/h, how far would the thief have run, before

the policeman caught up with him?

This questions was previously asked in

SSC CHSL 24th May 2022 Shift-3

1237.5 metres

1137.5 metres

1357.5 metres

1256.5 metres

- The problem involves calculating the distance the thief runs before being caught by the policeman.

- The initial distance between the thief and policeman is 225 meters.

- The thief runs at 11 km/h, and the policeman runs at 13 km/h.

- The relative speed of the policeman compared to the thief is (13 km/h - 11 km/h) = 2 km/h.

- Convert the relative speed to meters per second: $2 km/h = \frac{2 \times 1000}{60 \times 60} m/s = \frac{5}{9} m/s$ .

- The time taken for the policeman to close the 225-meter gap is $225 \div \frac{5}{9} = 405$ seconds.

- During this time, the thief runs $11 km/h = \frac{11 \times 1000}{60 \times 60} m/s = \frac{55}{18} m/s$ .

- The total distance the thief runs in 405 seconds is $405 \times \frac{55}{18} = 1237.5$ meters.

Option 1: 1237.5 meters is the correct answer.

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