A thief is noticed by a policeman from a distance of 650 m The thief starts running and the policema...........

Quantitative Aptitude (CHSL) Time & distance

A thief is noticed by a policeman from a distance of 650 m. The thief starts running and the policeman chases him. The thief

and the policeman run at the rate of 8 km and 10.5 km per hour, respectively. The distance (in metres) between them after 12

minutes is:

This questions was previously asked in

SSC CHSL 27th May 2022 Shift-2

150

125

100

- The initial distance between the thief and the policeman is 650 meters.

- The thief runs at a speed of 8 km/h, and the policeman runs at 10.5 km/h.

- Convert these speeds into meters per minute:

- Thief: \(8 \text{ km/h} = \frac{8 \times 1000}{60} \approx 133.33 \text{ m/min}\)

- Policeman: \(10.5 \text{ km/h} = \frac{10.5 \times 1000}{60} \approx 175 \text{ m/min}\)

- After 12 minutes, calculate the distance covered:

- Thief: \(133.33 \times 12 \approx 1600 \text{ m}\)

- Policeman: \(175 \times 12 = 2100 \text{ m}\)

- The relative distance between the two is \(2100 - 1600 = 500 \text{ meters} - 650\text{ meters}\). This results in a remaining gap of 150 meters.

- Option 1: 150 meters is the correct answer.

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