A train crosses a 400 m long platform in 50 seconds It crosses another 600 m long platform in 60 sec...........

Quantitative Aptitude (CHSL) Time & distance

A train crosses a 400 m-long platform in 50 seconds. It crosses another 600 m-long platform in 60 seconds. What are the

length and the speed of the train?

This questions was previously asked in

SSC CHSL 31st May 2022 Shift-1

600 m; 72 km/h

550 m; 75 km/h

500 m; 70 km/h

650 m; 74 km/h

- The formula for speed is distance over time.

- First crossing: Total distance = Train's length + 400 m, Time = 50 seconds.

- Second crossing: Total distance = Train's length + 600 m, Time = 60 seconds.

- Solve the equations for the train's length and speed:

- Equation 1: \((L + 400) / 50 = (L + 600) / 60\)

- Solve for L (Train's length).

- Calculate speed using either equation with found L.

- Option 1: 600 m; 72 km/h

- This satisfies the equations and conditions.

- Correct Answer

- Option 2: 550 m; 75 km/h

- Incorrect speed with given time.

- Option 3: 500 m; 70 km/h

- Incorrect speed and length.

- Option 4: 650 m; 74 km/h

- Incorrect speed with given time.

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