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A certain number of students from school X appeared in an examination and 20% students failed. From school Y, 130% more
students than that from school X, appeared in the same examination. If 90% of the total number of students appeared from
from both the schools passed, then what is the percentage of students from school Y whofailed (correct to one decimal place)?
6.4%
10%
5.7%
8.3%
- Let \( x \) be the number of students from school X.
- From school X, 20% failed, so 80% passed.
- From school Y, 130% more students than school X appeared, so \( 2.3x \) students appeared from school Y.
- Overall, 90% of total students from both schools passed.
- Let total students from both schools be \( x + 2.3x = 3.3x \).
- Total students passing = 0.9 \times 3.3x = 2.97x.
- Students passing from school X = 0.8x.
- Students passing from school Y = 2.97x - 0.8x = 2.17x.
- Therefore, students failed from school Y = \( 2.3x - 2.17x = 0.13x \).
- Percentage of students from school Y who failed = \(\left(\frac{0.13x}{2.3x}\right) \times 100 = 5.65\%\).
Option 3: 5.7%
By: santosh ProfileResourcesReport error
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