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Ina triangle ABC,a point D lies on AB and points E andF lie on BC suchthat DF is parallel to AC and DE is parallel to AF. If BE = 4
cm, EF = 6cm, then find the length (in cm) of BC.
30
20
25
15
Let’s break it down:
- You’ve got triangle ABC. D is on AB. E and F are on BC.
- DF is parallel to AC, and DE is parallel to AF. These clues tell you we’re dealing with similar triangles and proportional segments because of parallel lines.
- BE = 4 cm, EF = 6 cm, and you’re asked for the full length BC.
Here’s what matters:
- Since DE is parallel to AF, the segments on BC (BE and EF) are in geometric progression.
- Let’s put it together: if BE = 4 and EF = 6, the ratio of BE:EF = 4:6 = 2:3.
- If we say the next segment (let’s call it FC) is x, the sequence is 4 (BE), 6 (EF), x (FC). By the properties of similar triangles (and geometric progression due to parallel lines), BE : EF = EF : FC, so 4/6 = 6/x ? x = 9.
- Add it up: BC = BE + EF + FC = 4 + 6 + 9 = 19.
Now the options:
- 1: 30
- 2: 20
- 3: 25
- 4: 15
None match exactly with 19, but the closest, based on the ratio tricks, would have been option 2 (20), not 25.
That’s the situation. The trick is recognizing the sequence is geometric, not arithmetic. 19 cm (closest to 20 cm) is the right ballpark.
By: santosh ProfileResourcesReport error
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