send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
A and B, working together, can complete a work in d days. Working alone, A takes (8 + d) days and B takes (18 + d) days to
complete the same work. A works for 4 days. The remaining work will be completed by B alone, in:
24 days
16 days
18 days
20 days
To find the time when A and B, working together = d = $$\sqr{8 \times 18}$$ = 12 Time taken by A to complete the work = (8 + d) = 8 + 12 = 20 Time taken by B to complete the work = (18 + d) = 18 + 12 = 30 Let the total work be 60. (LCM of 20 and 30 is 60.) Efficiency of A = 60/20 = 3 Efficiency of B = 60/30 = 2 Work done by A in 4 days = efficiency $$\times time = 3 \times 4 = 12$$ Remaining work = 60 - 12 = 48 Time taken by B to complete the remaining work = 48/2 = 24 days $$\therefore$$ The remaining work will be completed by B alone, in 24 days.
Report error
Access to prime resources