The areas of and are 64 and 81 respectively and AD and PT are the medians of nb...........

Quantitative Aptitude (CGL) Geometry

$\bigtriangleup ABC\sim \bigtriangleup PQR$ The areas of $\bigtriangleup ABC$ and $\bigtriangleup PQR$ are 64 $CM^{^{2}}$ and 81 $CM^{^{2}}$ , respectively and AD and PT are the medians

of $\bigtriangleup ABC$ and $\bigtriangleup PQR$ , respectively. If PT = 10.8 cm, then AD =?

This questions was previously asked in

SSC CGL 13th August 2021 Shift-1

View All ssc Previous Year Papers

8.4 cm

9 cm

9.6 cm

12 cm

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Explanation:

9.6 cm

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The areas of and are 64 and 81 respectively and AD and PT are the medians of nb...........

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Explanation:

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