Explanation:

- We need to find the smallest multiple of 7 that leaves a remainder of 5 when divided by 8, 9, 12, and 15.

- Such a number can be expressed in the form 7k, where 7k = 5 (mod 8), 7k = 5 (mod 9), 7k = 5 (mod 12), and 7k = 5 (mod 15).

- This means that 7k-5 is divisible by 8, 9, 12, and 15.

- The least common multiple (LCM) of 8, 9, 12, and 15 is 360.

- So, 7k - 5 should be 360, or 720, or 1080, etc. Thus, 7k should be 365, 725, or 1085, etc.

- ? 1085 is indeed 7k and leaves 5 as a remainder with each of the given divisors.

- Option 1: 365 is not a multiple of 7.

- Option 3: 2525 is correct but not the smallest one.

- Option 4: 725 is a multiple but not the smallest.