At present A is younger than B by 8 years If 4 years ago their ages were in me ratio 1 2 then what i...........

Quantitative Aptitude (CGL) Problems based on Ages

At present, A is younger than B by 8 years. If 4 years ago, their ages were in me ratio 1 : 2, then what is the present age of B (in

years)?

This questions was previously asked in

SSC CGL 12th April 2022 Shift-1

- At present, let's assume A's age is "x" years and B's age is "x + 8" years, since A is younger by 8 years.

- Four years ago, A's age was "x - 4" and B's age was "(x + 8) - 4 = x + 4".

- According to the problem, four years ago, their ages were in the ratio of 1:2, hence:

\frac{x - 4}{x + 4} = \frac{1}{2}

- Solving this equation:

- Cross-multiply: 2(x - 4) = x + 4

- Expanding: 2x - 8 = x + 4

- Simplify: 2x - x = 4 + 8

- So, x = 12

- Therefore, B's current age: x + 8 = 12 + 8 = 20

- This makes Option 2: 20 the correct answer.

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