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A cylindrical tub of radius 10 cm contains water up to a depth of 25cm. A spherical iron ball is dropped into the tub and thus the level of water is raised by 5cm. What is the radius of the iron ball(approximate) ?

Explanation:

Answer & Explanation
Answer – 3.14
Explanation :
Volume of the ball = volume of the raised water
4*22*r3/3*7 = 22*100*5
r3 = 11000*3*7/88 = 2625
r = 13.79 or 14

By: MIRZA SADDAM HUSSAIN

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