4 kg of a metal contains 1/5 copper and rest in Zinc. Another 5 kg of metal contains 1/6 copper and rest in Zinc.The ratio of Copper and Zinc into the mixture of these two metals:
Explanation:
Copper in 4 kg = 4/5 kg
and Zinc in 4 kg = 4 x (4/5) kg
Copper in 5 kg = 5/6 kg
and Zinc in 5 kg = 5 x (5/6) kg
Therefore, Copper in mixture = 4/5 + 5/6 = 49/30kg
and Zinc in the mixture = 16/5 + 25/6 = 221/30kg
Therefore the required ratio = 49 : 221
Hence, option 2 is the correct answer.
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By: Amit Kumar